Solution :

First term = 24

a = 24

Common difference = t2 – t1

= 23 ¼ – 24

= (93/4) – 24

= (93-96)/4

d = -3/4

tn = a + (n - 1) d

Let us consider 3 as nth term

tn = 3

3 = 24 + (n-1) (-3/4)

3 – 24 = (n-1) (-3/4)

(-21 x 4)/(-3) = n -1

84/3 = n -1

28 = n – 1

28 + 1 = n

n = 29

Hence, 29th term of and A.P is 3.