Solution:
9th term = 0
t₉ = 0
a + 8 d = 0
a = -8d
t₂₉ = a + 28 d
= -8 d + 28 d
= 20 d
= 2[10 d]
= 2 [-8d + 18 d]
= 2[a + 18 d]
t₂₉ = 2[t₁₉]
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