Cinemugam (Kollywood)

Ans. According to Newton's second law, "The force acting on a body is directly proportional to the rate of change of linear momentum of the body and the change in momentum takes place in the direction of the force.

Ans. Based on the direction and application, forces can be classified into, i. Like parallel forces ii. Unlike parallel forces.

1. The inherent property of a body to resist any change in its state of rest or the state of uniform motion, unless it is influenced upon by an external unbalanced force, is known as inertia. 2. It is classified into three types, i. inertia of rest ii. inertia of motion iii. inertia of direction.

Assertion and Reasoning. 1. Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments. Reason: The principle of conservation of momentum is valid if the external force on the system is zero. a. If both the assertion and the reason are true and the reason is the correct explanation of the assertion. b. If both the assertion and the reason are true, but the reason is not the correct explanation of the assertion. c. Assertion is true, but the reason is false. d. Assertion is false, but the reason is true. Ans. b. If both the assertion and the reason are true, but the reason is not the correct explanation of the assertion. 2. Assertion: The value of 'g' decreases as height and depth increases from the surface of the Earth. Reason: 'g' depends on the mass of the object and the Earth. a. If both the assertion and the reason are true and the reason is the correct explanation of the assertion. b. If both the ass

Column I Column II 1. Newton's I law a. Propulsion of a rocket. 2. Newton's II law b. Stable equilibrium of a body. 3. Newton's III law c. Law of force 4. Law of conservation of linear momentum d. Flying nature of bird Column I Answers 1. Newton's I law b. Stable equilibrium of a body. 2. Newton's II law c. Law of force. 3. Newton's III law d. Flying nature of bird. 4. Law of conservation of linear momentum a. propulsion of a rocket.

1. The linear momentum of a system of particles is always conserved. Ans. False. In the absence of an external force, the linear momentum of a system of particles is always conserved. 2. Apparent weight of a person is always equal to his actual weight. Ans. False. Apparent weight of a person is not equal to his actual weight. 3. Weight of a body is greater at the equator and less at the polar region. Ans. False. Weight of a body is greater at the polar region and less at the equator. 4. Turning a nut with a spanner having a short handle is so easy than one with a long handle. Ans. False. Turning a nut with  a spanner having a long handle is so easy than one with a short handle. 5. There is no gravity in the orbiting space station around the Earth. So the astronauts feel weightlessness. Ans. False. Astronauts are falling freely around the Earth due to their huge orbital velocity.

MATHS SSLC 10TH QUARTERLY MODEL QUESTION PAPER – 2019 2020 10th MATHS Quarterly Exam 2019 Original Question Paper September 2019 WITH SOLUTION Tamil Medium 10th MATHS Quarterly Exam 2019 Original Question Paper September 2019 WITH SOLUTION 10th std maths New Syllabus, (TN), 2019 - 2020.  1. RELATIONS AND FUNCTIONS. EX. NO. 1.1 EX. NO. 1.2 EX. NO. 1.3 EX. NO. 1.4 EX. NO. 1.5 UNIT EXERCISE 1   2. NUMBERS AND SEQUENCES EX. NO. 2.1 EX. NO. 2.2 EX. NO. 2.3 EX. NO. 2.4 EX. NO. 2.5 EX. NO. 2.6 EX. NO. 2.7 EX. NO. 2.8 EX. NO. 2.9 EX. NO. 2.10 UNIT EXERCISE 2 Maths Study Material 10th Maths - Unit 4 Study Materials | Mr. M. Palaniyappan - English Medium Download Here 10th Maths - 25% Portion Model Question Paper | Mr. Renugopal - English Medium Download Here 10th Maths - Exam 2020 Blueprint | Mr. Abdul Munab - English Medium Download Here 10th Maths - Chapter 6 Study Materials | Mr. K. Kannan - English Medium Download Here 10th Maths -

EX. NO. 1.3, RELATIONS AND FUNCTIONS, 10TH MATHS NEW SYLLABUS, TAMIL NADU, TN, 1. Let f = {(x, y) | x, y ∈ N and y = 2x} be a relation on ℕ. Find the domain, co-domain and range. Is this relation a function? Solution : Since x and y ∈ N, x = 1 y = 2(1) y = 2 x = 2 y = 2(2) y = 4 x = 3 y = 2(3) y = 6 x = 4 y = 2(4) y = 8 f = {(1, 2) (2, 4) (3, 6) (4, 8)................} For each values of x, we get different values of y. So the given relation is a function. Domain is the set of values of x Domain  = {1, 2, 3, 4, ............} Co domain is the set of value of y. Since y ∈ N Co domain  = {1, 2, 3, 4, .............} Range means the set of values of y, which are associated with x. Range =  {2, 4, 6, 8, .....} 2. Let X = {3, 4, 6, 8}. Determine whether the relation ℝ  = {(x, f (x)) | x ∈ X, f (x) = x 2 + 1} is a function from X to ℕ ? Solution : Given that : f (x) = x 2 + 1 x ∈ X if x = 3 f(3) = 3 2 +1 f(