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Find the first four terms of the sequence whose nth terms are given by (i) an = n3 −2
Find the first four terms of the sequence whose nth terms are given by
(i) a
n
= n
3
−2
Solution :
To find the 1st term, we have to apply n = 1
a
n
= n
3
−2
n = 1
a
1
= 1
3
−2
= 1 - 2
a
1
= -1
a
n
= n
3
−2
n = 2
a
2
= 2
3
−2
= 8 - 2
a
2
= 6
a
n
= n
3
−2
n = 3
a
3
= 3
3
−2
= 27 - 2
a
3
= 25
a
n
= n
3
−2
n = 4
a
4
= 4
3
−2
= 64 - 2
a
4
= 62
Hence the first four terms are -1, 6, 25, 62.
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