Find the sum
Solution :
a = (a-b)/(a+b)
d = (3a-2b)/(a+b) - (a-b)/(a+b)
d = [3a - 2b -(a - b)]/(a + b)
d = [3a - 2b -a + b]/(a + b)
d = (2a - b) / (a + b)
Sn = (n/2)[2a + (n - 1)d]
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