Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2.

Solution :

8th term is 768

t8 = 768

ar7 = 768

r = 2

a(27) = 768

a = 768/128

a = 6

10th term :

t10 = ar9

= 6(29)

= 6(512)

t10 = 3072

Hence the 10th term of the sequence is 3072.