### Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2.

Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2.
Solution :
8th term is 768
t8  = 768
ar7  = 768
r = 2
a(27)  = 768
a  = 768/128
a = 6
10th term :
t10  = ar9
=  6(29)
=  6(512)
t10  =  3072
Hence the 10th term of the sequence is 3072.