Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2.
Solution :
8th term is 768
t8 = 768
ar7 = 768
r = 2
a(27) = 768
a = 768/128
a = 6
10th term :
t10 = ar9
= 6(29)
= 6(512)
t10 = 3072
Hence the 10th term of the sequence is 3072.