In a G.P. the 9th term is 32805 and 6th term is 1215. Find the 12th term.

In a G.P. the 9th term is 32805 and 6th term is 1215. Find the 12th term.
Solution :
9th term is 32805
t9  = 32805
ar8  = 32805   -----(1)
6th term is 1215
t6  = 1215
ar5  = 1215  -----(2)
(2) / (1)  ==> ar5/ar8  = 1215/32805
1/r3  = 1/27
(1/r)3  = (1/3)3
r = 3
By applying the value of r in (2), we get
a(3)5  = 1215  
a  = 1215/35
a  = 5(35)/35
a = 5
12th term :
t12  =  ar11
t12   =  5(3)11