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Find a8 and a15 whose nth term is
Find a
8
and a
15
whose nth term is
Solution :
In a
8,
8 is even in a
15
, 15 is odd
a
n
= (n
2
- 1)/(n + 3)
a
8
= (8
2
- 1)/(8 + 3)
= (64 - 1)/11
= 63/11
a
n
= n
2
/(2n + 1)
a
15
= 15
2
/(2(15) + 1)
= 225/(30 + 1)
= 225/31
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