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In a G.P. 729, 243, 81,… find t7 .

In a G.P. 729, 243, 81,… find t7 .
Solution :
tn  = ar n -1
a = 729, r = 243/729  = 1/3 and n = 7
t7  = (729) (1/3)7 -1
 =  (729) (1/3)6
t7   = 1